Molar volume is defined as the volume of one mole substance, one mole consists of 6.023×10^{23} atoms. Molar volume is directly proportional to molar mass and inversely proportional to the density. In the case of volatile liquid, this formula helps to find out the molar mass. The formula for molar volume is given as,

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Solved problems of molar volume are given below:

### Solved Examples

**Question 1: **Determine the molar volume of ice? Given density = 0.9167g/cm3, molar mass = 18g and atomic weight is 18.02g.

** Solution: **

Given parameters are,

Density, $\rho$ = 0.9167g/cm^{3}, molar mass = 18g =0.018kg and atomic weight = 18.02g.

The formula for molar volume is,

$V_{m}$ = $\frac{Atomic\ weight\times Molar\ mass}{Density}$

$V_{m}$ = $\frac{18.02\times 0.018}{0.0009167}$ = 353.83m^{3}/mol

**Question 2: **The decomposition of NaClO_{3 }results the production of NaCl and O_{2}. Calculate the volume of O_{2} if 42.6g NaClO_{3} decomposes at STP? The density is given as 0.213kg/m^{3}.

** Solution: **

Given parameters are,

Density, $\rho$ = 0.213kg/m^{3}, molar mass = 42.6g/mol = 0.0426kg/mol and atomic weight = 96.

The formula for molar volume is,

$V_{m}$ = $\frac{Atomic\ weight\times Molar\ mass}{Density}$

$V_{m}$ = $\frac{96\times 0.0426}{0.213}$ = 19.2m^{3}/mol

Given parameters are,

Density, $\rho$ = 0.9167g/cm

The formula for molar volume is,

$V_{m}$ = $\frac{Atomic\ weight\times Molar\ mass}{Density}$

$V_{m}$ = $\frac{18.02\times 0.018}{0.0009167}$ = 353.83m

Given parameters are,

Density, $\rho$ = 0.213kg/m

The formula for molar volume is,

$V_{m}$ = $\frac{Atomic\ weight\times Molar\ mass}{Density}$

$V_{m}$ = $\frac{96\times 0.0426}{0.213}$ = 19.2m