We have few basic formals that are used to calculate the probability and they are stated as:

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Below are the problems on based on probability :

### Solved Examples

**Question 1: **Calculate the probability of getting an odd number if a die is rolled?

** Solution: **

Sample space(S) if a die is rolled = {1, 2, 3, 4, 5, 6}

Let "E" be the event of getting an odd number, E = {1, 3, 5}

So, the Probability of getting an odd number P(E) = $\frac{Number\ of\ outcomes\ favorable}{Total\ number\ of\ outcomes}$ = $\frac{n(E)}{n(S)}$ = $\frac{3}{6}$ = $\frac{1}{2}$

**Question 2: **If two coins are tossed, then calculate the probability of getting two tails?

** Solution: **

Sample space(S), when two coins are tossed = {(H, H), (H, T), (T, H), (T, T) } = 4

Let "E" is the event of getting an odd number, E = {(T, T)} = 1

So, the Probability of getting an odd number P(E) = $\frac{Number\ of\ outcomes\ favorable}{Total\ number\ of\ outcomes}$ = $\frac{n(E)}{n(S)}$ = $\frac{1}{4}$

Sample space(S) if a die is rolled = {1, 2, 3, 4, 5, 6}

Let "E" be the event of getting an odd number, E = {1, 3, 5}

So, the Probability of getting an odd number P(E) = $\frac{Number\ of\ outcomes\ favorable}{Total\ number\ of\ outcomes}$ = $\frac{n(E)}{n(S)}$ = $\frac{3}{6}$ = $\frac{1}{2}$

Sample space(S), when two coins are tossed = {(H, H), (H, T), (T, H), (T, T) } = 4

Let "E" is the event of getting an odd number, E = {(T, T)} = 1

So, the Probability of getting an odd number P(E) = $\frac{Number\ of\ outcomes\ favorable}{Total\ number\ of\ outcomes}$ = $\frac{n(E)}{n(S)}$ = $\frac{1}{4}$