A **pyramid **is a polyhedron with a polygonal base and triangular
faces equal to the number of sides in the base. All the triangular faces meet at a single point called the **apex**.
The faces of the pyramid connect the bases with the apex. If the pyramid is oblique leaning to one side or the base is irregular, there is no straightforward way to find the surface area. Each triangular face will be a different shape and size, so you would have to find the area of each using whatever measurements you are given.

Types of Pyramids

There are many types of Pyramids, and they are named after the shape of their base. Surface Area of a Pyramid is the sum of the area of the polygonal base and the area of the triangular faces.

Types of Pyramids

There are many types of Pyramids, and they are named after the shape of their base. Surface Area of a Pyramid is the sum of the area of the polygonal base and the area of the triangular faces.

The

Where,

a - apothem length of the pyramid.

b - base length of the pyramid.

s - slant height of the pyramid.

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Surface Area of a Pyramid Calculator | Surface Area of a Square Pyramid |

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Some solved problems on the surface area of a pyramid are given below :

### Solved Examples

**Question 1: **Find the surface area of a hexagonal pyramid of apothem length 3 cm, base length 5 cm, and slant height 10 cm ?

** Solution: **

Given,

a = 3 cm

b = 5 cm

s = 10 cm^{
}Surface area of a hexagonal pyramid

= 3ab + 3bs

= (3 $\times$ 3 cm $\times$ 5 cm) + (3 $\times$ 5 cm $\times$ 10 cm)

= 45 cm^{2} + 150 cm^{2
}= 195 cm^{2}

**Question 2: **Find the surface area of a pentagonal pyramid of apothem length 9 cm, base length 12 cm, and slant height 21 cm ?

** Solution: **

Given,

a = 9 cm

b = 12 cm

s = 21 cm

Surface area of a pentagonal pyramid

= $\frac{5}{2}$ab + $\frac{5}{2}$bs

= $\frac{5}{2}$(9 cm $\times$ 12 cm) + $\frac{5}{2}$(12 cm $\times$ 21 cm)

= 270 cm^{2} + 630 cm^{2
}= 900 cm^{2}

Given,

a = 3 cm

b = 5 cm

s = 10 cm

= 3ab + 3bs

= (3 $\times$ 3 cm $\times$ 5 cm) + (3 $\times$ 5 cm $\times$ 10 cm)

= 45 cm

Given,

a = 9 cm

b = 12 cm

s = 21 cm

Surface area of a pentagonal pyramid

= $\frac{5}{2}$ab + $\frac{5}{2}$bs

= $\frac{5}{2}$(9 cm $\times$ 12 cm) + $\frac{5}{2}$(12 cm $\times$ 21 cm)

= 270 cm

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