Where **Q** is the thermal energy, **m** is the mass of the given substance, **c** is the specific heat and **ΔT** is the temperature difference.

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Let us discuss the problems of thermal energy.

### Solved Examples

**Question 1: **Calculate the thermal energy of a substance whose mass is 3kg and specific heat is 0.038J/kg°C. The temperature difference of this system is given as 60°C?

** Solution: **

From the question, it is clear that,

m = 3kg, c = 0.038J/kg°C, ΔT = 60°C

The formula for thermal energy is

Q = mc$\Delta$T

Q = 3$\times$0.038$\times$60 = 6.84J

**Question 2: **2kg substance undergo a temperature difference of 50°C whose specific heat is 0.05J/kg°C, calculate the thermal energy?

** Solution: **

From the question, it is clear that,

m = 2kg, c = 0.05J/kg°C, ΔT = 50°C

The formula for thermal energy is

Q = mc$\Delta$T

Q = 2$\times$0.05$\times$50 = 5J

From the question, it is clear that,

m = 3kg, c = 0.038J/kg°C, ΔT = 60°C

The formula for thermal energy is

Q = mc$\Delta$T

Q = 3$\times$0.038$\times$60 = 6.84J

From the question, it is clear that,

m = 2kg, c = 0.05J/kg°C, ΔT = 50°C

The formula for thermal energy is

Q = mc$\Delta$T

Q = 2$\times$0.05$\times$50 = 5J